sched: Fix /proc/sched_debug failure on very very large systems
On systems with 4096 cores attemping to read /proc/sched_debug
fails because we are trying to push all the data into a single
kmalloc buffer.
The issue is on these very large machines all the data will not
fit in 4mb.
A better solution is to not us the single_open mechanism but to
provide our own seq_operations and treat each cpu as an
individual record.
The output should be identical to the previous version.
Reported-by: Dave Jones <davej@redhat.com>
Signed-off-by: Nathan Zimmer <nzimmer@sgi.com>
Cc: Peter Zijlstra <peterz@infradead.org>)
[ Whitespace fixlet]
[ Fix spello in comment]
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Ingo Molnar <mingo@kernel.org>
diff --git a/kernel/sched/debug.c b/kernel/sched/debug.c
index 7ae4c4c..c496eb3 100644
--- a/kernel/sched/debug.c
+++ b/kernel/sched/debug.c
@@ -269,11 +269,11 @@
{
unsigned int freq = cpu_khz ? : 1;
- SEQ_printf(m, "\ncpu#%d, %u.%03u MHz\n",
+ SEQ_printf(m, "cpu#%d, %u.%03u MHz\n",
cpu, freq / 1000, (freq % 1000));
}
#else
- SEQ_printf(m, "\ncpu#%d\n", cpu);
+ SEQ_printf(m, "cpu#%d\n", cpu);
#endif
#define P(x) \
@@ -330,6 +330,7 @@
print_rq(m, rq, cpu);
rcu_read_unlock();
spin_unlock_irqrestore(&sched_debug_lock, flags);
+ SEQ_printf(m, "\n");
}
static const char *sched_tunable_scaling_names[] = {
@@ -338,11 +339,10 @@
"linear"
};
-static int sched_debug_show(struct seq_file *m, void *v)
+static void sched_debug_header(struct seq_file *m)
{
u64 ktime, sched_clk, cpu_clk;
unsigned long flags;
- int cpu;
local_irq_save(flags);
ktime = ktime_to_ns(ktime_get());
@@ -384,33 +384,101 @@
#undef PN
#undef P
- SEQ_printf(m, " .%-40s: %d (%s)\n", "sysctl_sched_tunable_scaling",
+ SEQ_printf(m, " .%-40s: %d (%s)\n",
+ "sysctl_sched_tunable_scaling",
sysctl_sched_tunable_scaling,
sched_tunable_scaling_names[sysctl_sched_tunable_scaling]);
-
- for_each_online_cpu(cpu)
- print_cpu(m, cpu);
-
SEQ_printf(m, "\n");
+}
+
+static int sched_debug_show(struct seq_file *m, void *v)
+{
+ int cpu = (unsigned long)(v - 2);
+
+ if (cpu != -1)
+ print_cpu(m, cpu);
+ else
+ sched_debug_header(m);
return 0;
}
void sysrq_sched_debug_show(void)
{
- sched_debug_show(NULL, NULL);
+ int cpu;
+
+ sched_debug_header(NULL);
+ for_each_online_cpu(cpu)
+ print_cpu(NULL, cpu);
+
+}
+
+/*
+ * This itererator needs some explanation.
+ * It returns 1 for the header position.
+ * This means 2 is cpu 0.
+ * In a hotplugged system some cpus, including cpu 0, may be missing so we have
+ * to use cpumask_* to iterate over the cpus.
+ */
+static void *sched_debug_start(struct seq_file *file, loff_t *offset)
+{
+ unsigned long n = *offset;
+
+ if (n == 0)
+ return (void *) 1;
+
+ n--;
+
+ if (n > 0)
+ n = cpumask_next(n - 1, cpu_online_mask);
+ else
+ n = cpumask_first(cpu_online_mask);
+
+ *offset = n + 1;
+
+ if (n < nr_cpu_ids)
+ return (void *)(unsigned long)(n + 2);
+ return NULL;
+}
+
+static void *sched_debug_next(struct seq_file *file, void *data, loff_t *offset)
+{
+ (*offset)++;
+ return sched_debug_start(file, offset);
+}
+
+static void sched_debug_stop(struct seq_file *file, void *data)
+{
+}
+
+static const struct seq_operations sched_debug_sops = {
+ .start = sched_debug_start,
+ .next = sched_debug_next,
+ .stop = sched_debug_stop,
+ .show = sched_debug_show,
+};
+
+static int sched_debug_release(struct inode *inode, struct file *file)
+{
+ seq_release(inode, file);
+
+ return 0;
}
static int sched_debug_open(struct inode *inode, struct file *filp)
{
- return single_open(filp, sched_debug_show, NULL);
+ int ret = 0;
+
+ ret = seq_open(filp, &sched_debug_sops);
+
+ return ret;
}
static const struct file_operations sched_debug_fops = {
.open = sched_debug_open,
.read = seq_read,
.llseek = seq_lseek,
- .release = single_release,
+ .release = sched_debug_release,
};
static int __init init_sched_debug_procfs(void)