debugfs: make debugfs_create_u32_array() return void
The single user of debugfs_create_u32_array() does not care about the
return value of it, so make it return void as there is no need to do
anything with the return value.
Signed-off-by: Greg Kroah-Hartman <gregkh@linuxfoundation.org>
diff --git a/Documentation/filesystems/debugfs.txt b/Documentation/filesystems/debugfs.txt
index 4a0a9c3..9e27c84 100644
--- a/Documentation/filesystems/debugfs.txt
+++ b/Documentation/filesystems/debugfs.txt
@@ -169,7 +169,7 @@
If you want to dump an u32 array in debugfs, you can create file with:
- struct dentry *debugfs_create_u32_array(const char *name, umode_t mode,
+ void debugfs_create_u32_array(const char *name, umode_t mode,
struct dentry *parent,
u32 *array, u32 elements);
