| /* |
| * Copyright (C) 2006-2010 B.A.T.M.A.N. contributors: |
| * |
| * Simon Wunderlich, Marek Lindner |
| * |
| * This program is free software; you can redistribute it and/or |
| * modify it under the terms of version 2 of the GNU General Public |
| * License as published by the Free Software Foundation. |
| * |
| * This program is distributed in the hope that it will be useful, but |
| * WITHOUT ANY WARRANTY; without even the implied warranty of |
| * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU |
| * General Public License for more details. |
| * |
| * You should have received a copy of the GNU General Public License |
| * along with this program; if not, write to the Free Software |
| * Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA |
| * 02110-1301, USA |
| * |
| */ |
| |
| #include "main.h" |
| #include "bitarray.h" |
| |
| /* returns true if the corresponding bit in the given seq_bits indicates true |
| * and curr_seqno is within range of last_seqno */ |
| uint8_t get_bit_status(TYPE_OF_WORD *seq_bits, uint16_t last_seqno, |
| uint16_t curr_seqno) |
| { |
| int16_t diff, word_offset, word_num; |
| |
| diff = last_seqno - curr_seqno; |
| if (diff < 0 || diff >= TQ_LOCAL_WINDOW_SIZE) { |
| return 0; |
| } else { |
| /* which word */ |
| word_num = (last_seqno - curr_seqno) / WORD_BIT_SIZE; |
| /* which position in the selected word */ |
| word_offset = (last_seqno - curr_seqno) % WORD_BIT_SIZE; |
| |
| if (seq_bits[word_num] & 1 << word_offset) |
| return 1; |
| else |
| return 0; |
| } |
| } |
| |
| /* turn corresponding bit on, so we can remember that we got the packet */ |
| void bit_mark(TYPE_OF_WORD *seq_bits, int32_t n) |
| { |
| int32_t word_offset, word_num; |
| |
| /* if too old, just drop it */ |
| if (n < 0 || n >= TQ_LOCAL_WINDOW_SIZE) |
| return; |
| |
| /* which word */ |
| word_num = n / WORD_BIT_SIZE; |
| /* which position in the selected word */ |
| word_offset = n % WORD_BIT_SIZE; |
| |
| seq_bits[word_num] |= 1 << word_offset; /* turn the position on */ |
| } |
| |
| /* shift the packet array by n places. */ |
| void bit_shift(TYPE_OF_WORD *seq_bits, int32_t n) |
| { |
| int32_t word_offset, word_num; |
| int32_t i; |
| |
| if (n <= 0 || n >= TQ_LOCAL_WINDOW_SIZE) |
| return; |
| |
| word_offset = n % WORD_BIT_SIZE;/* shift how much inside each word */ |
| word_num = n / WORD_BIT_SIZE; /* shift over how much (full) words */ |
| |
| for (i = NUM_WORDS - 1; i > word_num; i--) { |
| /* going from old to new, so we don't overwrite the data we copy |
| * from. |
| * |
| * left is high, right is low: FEDC BA98 7654 3210 |
| * ^^ ^^ |
| * vvvv |
| * ^^^^ = from, vvvvv =to, we'd have word_num==1 and |
| * word_offset==WORD_BIT_SIZE/2 ????? in this example. |
| * (=24 bits) |
| * |
| * our desired output would be: 9876 5432 1000 0000 |
| * */ |
| |
| seq_bits[i] = |
| (seq_bits[i - word_num] << word_offset) + |
| /* take the lower port from the left half, shift it left |
| * to its final position */ |
| (seq_bits[i - word_num - 1] >> |
| (WORD_BIT_SIZE-word_offset)); |
| /* and the upper part of the right half and shift it left to |
| * it's position */ |
| /* for our example that would be: word[0] = 9800 + 0076 = |
| * 9876 */ |
| } |
| /* now for our last word, i==word_num, we only have the it's "left" |
| * half. that's the 1000 word in our example.*/ |
| |
| seq_bits[i] = (seq_bits[i - word_num] << word_offset); |
| |
| /* pad the rest with 0, if there is anything */ |
| i--; |
| |
| for (; i >= 0; i--) |
| seq_bits[i] = 0; |
| } |
| |
| static void bit_reset_window(TYPE_OF_WORD *seq_bits) |
| { |
| int i; |
| for (i = 0; i < NUM_WORDS; i++) |
| seq_bits[i] = 0; |
| } |
| |
| |
| /* receive and process one packet within the sequence number window. |
| * |
| * returns: |
| * 1 if the window was moved (either new or very old) |
| * 0 if the window was not moved/shifted. |
| */ |
| char bit_get_packet(TYPE_OF_WORD *seq_bits, int16_t seq_num_diff, |
| int8_t set_mark) |
| { |
| /* sequence number is slightly older. We already got a sequence number |
| * higher than this one, so we just mark it. */ |
| |
| if ((seq_num_diff <= 0) && (seq_num_diff > -TQ_LOCAL_WINDOW_SIZE)) { |
| if (set_mark) |
| bit_mark(seq_bits, -seq_num_diff); |
| return 0; |
| } |
| |
| /* sequence number is slightly newer, so we shift the window and |
| * set the mark if required */ |
| |
| if ((seq_num_diff > 0) && (seq_num_diff < TQ_LOCAL_WINDOW_SIZE)) { |
| bit_shift(seq_bits, seq_num_diff); |
| |
| if (set_mark) |
| bit_mark(seq_bits, 0); |
| return 1; |
| } |
| |
| /* sequence number is much newer, probably missed a lot of packets */ |
| |
| if ((seq_num_diff >= TQ_LOCAL_WINDOW_SIZE) |
| || (seq_num_diff < EXPECTED_SEQNO_RANGE)) { |
| bat_dbg(DBG_BATMAN, |
| "We missed a lot of packets (%i) !\n", |
| seq_num_diff - 1); |
| bit_reset_window(seq_bits); |
| if (set_mark) |
| bit_mark(seq_bits, 0); |
| return 1; |
| } |
| |
| /* received a much older packet. The other host either restarted |
| * or the old packet got delayed somewhere in the network. The |
| * packet should be dropped without calling this function if the |
| * seqno window is protected. */ |
| |
| if ((seq_num_diff <= -TQ_LOCAL_WINDOW_SIZE) |
| || (seq_num_diff >= EXPECTED_SEQNO_RANGE)) { |
| |
| bat_dbg(DBG_BATMAN, |
| "Other host probably restarted!\n"); |
| |
| bit_reset_window(seq_bits); |
| if (set_mark) |
| bit_mark(seq_bits, 0); |
| |
| return 1; |
| } |
| |
| /* never reached */ |
| return 0; |
| } |
| |
| /* count the hamming weight, how many good packets did we receive? just count |
| * the 1's. The inner loop uses the Kernighan algorithm, see |
| * http://graphics.stanford.edu/~seander/bithacks.html#CountBitsSetKernighan |
| */ |
| int bit_packet_count(TYPE_OF_WORD *seq_bits) |
| { |
| int i, hamming = 0; |
| TYPE_OF_WORD word; |
| |
| for (i = 0; i < NUM_WORDS; i++) { |
| word = seq_bits[i]; |
| |
| while (word) { |
| word &= word-1; |
| hamming++; |
| } |
| } |
| return hamming; |
| } |