| // SPDX-License-Identifier: GPL-2.0-or-later | |
| /* -*- linux-c -*- ------------------------------------------------------- * | |
| * | |
| * Copyright 2002 H. Peter Anvin - All Rights Reserved | |
| * | |
| * ----------------------------------------------------------------------- */ | |
| /* | |
| * raid6/recov.c | |
| * | |
| * RAID-6 data recovery in dual failure mode. In single failure mode, | |
| * use the RAID-5 algorithm (or, in the case of Q failure, just reconstruct | |
| * the syndrome.) | |
| */ | |
| #include <linux/export.h> | |
| #include <linux/raid/pq.h> | |
| /* Recover two failed data blocks. */ | |
| static void raid6_2data_recov_intx1(int disks, size_t bytes, int faila, | |
| int failb, void **ptrs) | |
| { | |
| u8 *p, *q, *dp, *dq; | |
| u8 px, qx, db; | |
| const u8 *pbmul; /* P multiplier table for B data */ | |
| const u8 *qmul; /* Q multiplier table (for both) */ | |
| p = (u8 *)ptrs[disks-2]; | |
| q = (u8 *)ptrs[disks-1]; | |
| /* Compute syndrome with zero for the missing data pages | |
| Use the dead data pages as temporary storage for | |
| delta p and delta q */ | |
| dp = (u8 *)ptrs[faila]; | |
| ptrs[faila] = (void *)raid6_empty_zero_page; | |
| ptrs[disks-2] = dp; | |
| dq = (u8 *)ptrs[failb]; | |
| ptrs[failb] = (void *)raid6_empty_zero_page; | |
| ptrs[disks-1] = dq; | |
| raid6_call.gen_syndrome(disks, bytes, ptrs); | |
| /* Restore pointer table */ | |
| ptrs[faila] = dp; | |
| ptrs[failb] = dq; | |
| ptrs[disks-2] = p; | |
| ptrs[disks-1] = q; | |
| /* Now, pick the proper data tables */ | |
| pbmul = raid6_gfmul[raid6_gfexi[failb-faila]]; | |
| qmul = raid6_gfmul[raid6_gfinv[raid6_gfexp[faila]^raid6_gfexp[failb]]]; | |
| /* Now do it... */ | |
| while ( bytes-- ) { | |
| px = *p ^ *dp; | |
| qx = qmul[*q ^ *dq]; | |
| *dq++ = db = pbmul[px] ^ qx; /* Reconstructed B */ | |
| *dp++ = db ^ px; /* Reconstructed A */ | |
| p++; q++; | |
| } | |
| } | |
| /* Recover failure of one data block plus the P block */ | |
| static void raid6_datap_recov_intx1(int disks, size_t bytes, int faila, | |
| void **ptrs) | |
| { | |
| u8 *p, *q, *dq; | |
| const u8 *qmul; /* Q multiplier table */ | |
| p = (u8 *)ptrs[disks-2]; | |
| q = (u8 *)ptrs[disks-1]; | |
| /* Compute syndrome with zero for the missing data page | |
| Use the dead data page as temporary storage for delta q */ | |
| dq = (u8 *)ptrs[faila]; | |
| ptrs[faila] = (void *)raid6_empty_zero_page; | |
| ptrs[disks-1] = dq; | |
| raid6_call.gen_syndrome(disks, bytes, ptrs); | |
| /* Restore pointer table */ | |
| ptrs[faila] = dq; | |
| ptrs[disks-1] = q; | |
| /* Now, pick the proper data tables */ | |
| qmul = raid6_gfmul[raid6_gfinv[raid6_gfexp[faila]]]; | |
| /* Now do it... */ | |
| while ( bytes-- ) { | |
| *p++ ^= *dq = qmul[*q ^ *dq]; | |
| q++; dq++; | |
| } | |
| } | |
| const struct raid6_recov_calls raid6_recov_intx1 = { | |
| .data2 = raid6_2data_recov_intx1, | |
| .datap = raid6_datap_recov_intx1, | |
| .valid = NULL, | |
| .name = "intx1", | |
| .priority = 0, | |
| }; | |
| #ifndef __KERNEL__ | |
| /* Testing only */ | |
| /* Recover two failed blocks. */ | |
| void raid6_dual_recov(int disks, size_t bytes, int faila, int failb, void **ptrs) | |
| { | |
| if ( faila > failb ) { | |
| int tmp = faila; | |
| faila = failb; | |
| failb = tmp; | |
| } | |
| if ( failb == disks-1 ) { | |
| if ( faila == disks-2 ) { | |
| /* P+Q failure. Just rebuild the syndrome. */ | |
| raid6_call.gen_syndrome(disks, bytes, ptrs); | |
| } else { | |
| /* data+Q failure. Reconstruct data from P, | |
| then rebuild syndrome. */ | |
| /* NOT IMPLEMENTED - equivalent to RAID-5 */ | |
| } | |
| } else { | |
| if ( failb == disks-2 ) { | |
| /* data+P failure. */ | |
| raid6_datap_recov(disks, bytes, faila, ptrs); | |
| } else { | |
| /* data+data failure. */ | |
| raid6_2data_recov(disks, bytes, faila, failb, ptrs); | |
| } | |
| } | |
| } | |
| #endif |